Code Salvage
- Integrated some code from the (soon to be obsolete) 2.0.0 branch, which is general in nature and will be needed. - And the corresponding unit tests.
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src/tests/lisp.t.cpp
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65
src/tests/lisp.t.cpp
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////////////////////////////////////////////////////////////////////////////////
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// taskwarrior - a command line task list manager.
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//
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// Copyright 2006 - 2010, Paul Beckingham, Federico Hernandez.
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// All rights reserved.
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//
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// This program is free software; you can redistribute it and/or modify it under
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// the terms of the GNU General Public License as published by the Free Software
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// Foundation; either version 2 of the License, or (at your option) any later
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// version.
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//
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// This program is distributed in the hope that it will be useful, but WITHOUT
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// ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS
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// FOR A PARTICULAR PURPOSE. See the GNU General Public License for more
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// details.
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//
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// You should have received a copy of the GNU General Public License along with
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// this program; if not, write to the
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//
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// Free Software Foundation, Inc.,
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// 51 Franklin Street, Fifth Floor,
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// Boston, MA
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// 02110-1301
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// USA
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//
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////////////////////////////////////////////////////////////////////////////////
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#include <iostream>
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#include "main.h"
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#include "test.h"
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#include "Context.h"
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#include "Lisp.h"
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Context context;
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////////////////////////////////////////////////////////////////////////////////
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int main (int argc, char** argv)
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{
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UnitTest test (6);
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// (one)
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// t -> "one" (no tags)
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// -> no child nodes
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Lisp l;
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Tree* t = l.parse ("(one)");
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// TODO When tegelsten/Tree is merged in, uncomment this.
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t->dump ();
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test.is (t->branches (), 1, "(one) -> 1 node under root");
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test.is ((*t)[0]->tags (), 0, "(one) -> 0 tags");
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test.is ((*t)[0]->branches (), 0, "(one) -> 0 child nodes");
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delete t;
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// (one two)
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// t -> "one" (tag: "two")
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// -> no child nodes
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t = l.parse ("(one two)");
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// TODO When tegelsten/Tree is merged in, uncomment this.
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t->dump ();
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test.is (t->branches (), 1, "(one two) -> 1 node under root");
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test.is ((*t)[0]->tags (), 1, "(one) -> 1 tag");
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test.is ((*t)[0]->branches (), 0, "(one two) -> 0 child nodes");
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delete t;
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return 0;
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}
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